Practice›Java Fundamentals›Module 8. Interfaces & Abstract Classes›8.2 Comparable

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8.2 Comparable — sort by name

Total: 0 / 3 pts

Practice mode — check each part and get hints as you go.

Task

Student is naturally ordered by score. Fill in sortByName so that it sorts the list alphabetically by name instead — without changing the Student class.

The program prints [Ada(90), Bo(70), Sam(55)].

Your solution

import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;

class Student implements Comparable<Student> {
    private String name;
    private int score;

    public Student(String name, int score) {
        this.name = name;
        this.score = score;
    }

    public String getName() {
        return name;
    }

    public int getScore() {
        return score;
    }

    public int compareTo(Student other) {
        return score - other.score;
    }

    public String toString() {
        return name + "(" + score + ")";
    }
}

public class Main {

    public static void sortByName(ArrayList<Student> list) {
        // sort by name instead of the natural order

    }

    public static void main(String[] args) {
        ArrayList<Student> l = new ArrayList<Student>();
        l.add(new Student("Sam", 55));
        l.add(new Student("Ada", 90));
        l.add(new Student("Bo", 70));
        sortByName(l);
        System.out.println(l);
    }
}

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